(x+3)^2-x-3=(x+3)(x+2)

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Solution for (x+3)^2-x-3=(x+3)(x+2) equation: 



(x+3)^2-x-3=(x+3)(x+2)

We move all terms to the left:

(x+3)^2-x-3-((x+3)(x+2))=0

We add all the numbers together, and all the variables

-1x+(x+3)^2-((x+3)(x+2))-3=0

We multiply parentheses ..

-((+x^2+2x+3x+6))-1x+(x+3)^2-3=0



We calculate terms in parentheses: -((+x^2+2x+3x+6)), so:

(+x^2+2x+3x+6)

We get rid of parentheses

x^2+2x+3x+6

We add all the numbers together, and all the variables

x^2+5x+6

Back to the equation:

-(x^2+5x+6)



We add all the numbers together, and all the variables

-1x-(x^2+5x+6)+(x+3)^2-3=0

We get rid of parentheses

-x^2-1x-5x+(x+3)^2-6-3=0

We add all the numbers together, and all the variables

-1x^2-6x+(x+3)^2-9=0

We move all terms containing x to the left, all other terms to the right

-1x^2-6x+(x+3)^2=9

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